The calculated spin only magnetic moment of Cr2+ ion is :

Question

The calculated spin only magnetic moment of Cr2+ ion is : (A) 3.87 BM (B) 4.90 BM (C) 5.92 BM (D) 2.84 BM

Tardigrade Admin · Accepted Answer

Electronic configuration of Cr=[Ar]3d5 4s1 Electronic configuration of Cr+2=[Ar]3d4 Number of unpaired electrons = 4 Spin only magnetic moment =√n(n+2)BM as n=4 ∴ μ=√4(4+2) =√24 =4.90 BM

Q. The calculated spin only magnetic moment of $C r^{2 +}$ ion is :

3.87 BM

4.90 BM

5.92 BM

2.84 BM

Electronic configuration of $C r = [A r] 3 d^{5} 4 s^{1}$
Electronic configuration of $C r^{+ 2} = [A r] 3 d^{4}$
Number of unpaired electrons $= 4$
Spin only magnetic moment $= n (n + 2) BM$ as $n = 4$
$∴ μ = 4 (4 + 2)$
$= 24$
$= 4.90 BM$

Q. The calculated spin only magnetic moment of Cr2+ ion is :