The calculated magnetic moment of a divalent ion of an atom with atomic number 24 in aqueous solution is

Question

The calculated magnetic moment of a divalent ion of an atom with atomic number 24 in aqueous solution is (A) 4.90 BM (B) 5.92 BM (C) 3.87 BM (D) 2.84 BM

Tardigrade Admin · Accepted Answer

24 M =1 s2, 2 s2, 2 p6, 3 s2, 3 p6, 3 d5, 4 s1 =[ Ar ] 3 d5 4 s1 M2+ =[ Ar ] 3 d4 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/fb9d566c785fc473d171228ba8eb7b08-.png" /> ∴ Number of unpaired electrons =4 ∴ Mognetic moment; μ=√n(n+2) ∴ μ=√4(4+2) =√24=4.90 BM

Q. The calculated magnetic moment of a divalent ion of an atom with atomic number $24$ in aqueous solution is

4.90 BM

5.92 BM

3.87 BM

2.84 BM

1.73 BM

$_{24} M = 1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{6}, 3 d^{5}, 4 s^{1}$

$= [A r] 3 d^{5} 4 s^{1}$

$M^{2 +} = [A r] 3 d^{4}$

$∴$ Number of unpaired electrons $= 4$

$∴$ Mognetic moment; $μ = n (n + 2)$

$∴ μ = 4 (4 + 2)$

$= 24 = 4.90 BM$

Q. The calculated magnetic moment of a divalent ion of an atom with atomic number 24 in aqueous solution is