The breaking tension of a string is 10 N. A particle tied to it is rotated along a circle of radius 0.5 m The maximum speed with which particle can be rotated without breaking the string is (The mass of particle is 100 g )

Question

The breaking tension of a string is 10 N. A particle tied to it is rotated along a circle of radius 0.5 m The maximum speed with which particle can be rotated without breaking the string is (The mass of particle is 100 g ) (A) √500 ms -1 (B) √50 ms -1 (C) √5 ms -1 (D) √0.5 ms -1

Tardigrade Admin · Accepted Answer

F max =(m v max 2/R) v max =√(F max ⋅ R/m)=√(10 N × 0.5 m /0.1 kg ) =√50 ms -1

Q. The breaking tension of a string is $10 N$ . A particle tied to it is rotated along a circle of radius $0.5 m$ The maximum speed with which particle can be rotated without breaking the string is (The mass of particle is $100 g)$

$500 m s^{- 1}$

$50 m s^{- 1}$

$5 m s^{- 1}$

$0.5 m s^{- 1}$

$F_{m a x} = \frac{m v _{m a x}^{2}}{R}$
$v_{m a x} = \frac{F _{m a x} \cdot R}{m} = \frac{10 N \times 0.5 m}{0.1 k g}$
$= 50 m s^{- 1}$

Q. The breaking tension of a string is 10N. A particle tied to it is rotated along a circle of radius 0.5m The maximum speed with which particle can be rotated without breaking the string is (The mass of particle is 100g)

500​ms−1

50​ms−1

5​ms−1

0.5​ms−1