The breaking stress of a wire of length l and radius r is 5 kg wt/m2 . The wire of length 2l and radius 2r of the same material will have breaking stress in (kwt/m2) :

Question

The breaking stress of a wire of length l and radius r is 5 kg wt/m2 . The wire of length 2l and radius 2r of the same material will have breaking stress in (kwt/m2) : (A) 5 (B) 20 (C) 80 (D) 10

Tardigrade Admin · Accepted Answer

From the formula F=(YA Δ L/L) Fbreaking stress propto (Yπ r2/L) Hence, (5/F2)=((Yπ r2/L)/(Yπ (4r2))2L)=(1/2) Therefore, F2=10 kwt text/m2

Q. The breaking stress of a wire of length $l$ and radius r is $5 k g wt / m^{2}$ . The wire of length $2 l$ and radius 2r of the same material will have breaking stress in $(k wt / m^{2})$ :

5

20

80

10

From the formula $F = \frac{Y A Δ L}{L}$ $F_{b re akin g s t ress} \propto \frac{Yπ r ^{2}}{L}$ Hence, $\frac{5}{F _{2}} = \frac{\frac{Yπ r ^{2}}{L}}{\frac{Yπ ( 4 r ^{2} )}{2 L}} = \frac{1}{2}$ Therefore, $F_{2} = 10 k wt / m^{2}$

Q. The breaking stress of a wire of length l and radius r is 5kgwt/m2 . The wire of length 2l and radius 2r of the same material will have breaking stress in (kwt/m2) :

5

20

80

10

From the formula F=LYAΔL​ Fbreakingstress​∝LYπr2​ Hence, F2​5​=2LYπ(4r2)​LYπr2​​=21​ Therefore, F2​=10kwt/m2

Q. The breaking stress of a wire of length $l$ and radius r is $5 k g wt / m^{2}$ . The wire of length $2 l$ and radius 2r of the same material will have breaking stress in $(k wt / m^{2})$ :

From the formula $F = \frac{Y A Δ L}{L}$ $F_{b re akin g s t ress} \propto \frac{Yπ r ^{2}}{L}$ Hence, $\frac{5}{F _{2}} = \frac{\frac{Yπ r ^{2}}{L}}{\frac{Yπ ( 4 r ^{2} )}{2 L}} = \frac{1}{2}$ Therefore, $F_{2} = 10 k wt / m^{2}$