The bond order of NO molecule is

Question

The bond order of NO molecule is (A)  1.5  (B)  2.0  (C)  2.5  (D)  3.0

Tardigrade Admin · Accepted Answer

Total number of electron in N O=15 Number of bonding electrons (Na)=10 No. of anti bonding electrons (Nb)=5 Bond order =(Nb-Na/2) Bond order =(10-5/2)=2.5

Q. The bond order of $NO$ molecule is

$1.5$

$2.0$

$2.5$

$3.0$

Total number of electron in $NO = 15$
Number of bonding electrons $(N_{a}) = 10$
No. of anti bonding electrons $(N_{b}) = 5$
Bond order $= \frac{N _{b} - N _{a}}{2}$
Bond order $= \frac{10 - 5}{2} = 2.5$

Q. The bond order of NO molecule is

1.5

2.0

2.5

3.0