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  4. The bond order of NO molecule is

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Q. The bond order of $ NO $ molecule is

Chhattisgarh PMTChhattisgarh PMT 2005

Solution:

Total number of electron in $N O=15$
Number of bonding electrons $\left(N_{a}\right)=10$
No. of anti bonding electrons $\left(N_{b}\right)=5$
Bond order $=\frac{N_{b}-N_{a}}{2}$
Bond order $=\frac{10-5}{2}=2.5$