Question

The bond order of $N_2^{+}$on the basis of molecular orbital theory is [Atomic number of $N=7$ ]

• A. 3
• B. 2.5
• C. 2
• D. 1.5

Answer 1

Answer: (B)

We know that N3 molecule is having $14$ electrons so.
$N_2=14$
$N_2^{+}=14-1=13,$
according to MOT (Molecular orbital theory) the configruation will be
$N_2^{+}=KK\sigma 2S^2{\sigma }^{\ast }2S^2\pi 2p_x^2\pi 2p_y^2\sigma 2p_z^1$
Bond order $=\frac{1}{2}$ [Bonding - Antibonding]
$=\frac{1}{2}[7-2]=2\frac{1}{2}=2.5$