Bond energy of O-H is 109 k cal/mol means that when one mole of O-H bond is formed 109 k cal energy is released (because dissociation of bond absorbs energy). Formation of one mole of water is equivalent to formation of 2 moles of O-H bonds (H-O-H)
Hence energy released = 2 ×109 = 218 k cal
(Strictly speaking we calculate ΔfH ∘4 for the reaction H2(g)+1/2O2(g)→H2O(l)(H−O−H) ΔfH∘=BE(H−H)+1/2BE(O=O)−2BE(O - H)