The bond dissociation energy of Cl 2, Br 2 and I 2 follow the order

Question

The bond dissociation energy of Cl 2, Br 2 and I 2 follow the order (A) C l2>I2>B r2 (B) I2>B r2>C l2 (C) I2=C l2=B r2 (D) C l2>B r2>I2

Tardigrade Admin · Accepted Answer

As we move from top to bottom in halogen family the bond energy of the molecules decreases as the bond distance increases. As the bond distance increases it requires less energy to break the bond i.e. less bond energy.
So, the order of bond energy of the molecules is

C l_{2} > B r_{2} > I_{2}

.

Q. The bond dissociation energy of $C l_{2}, B r_{2}$ and $I_{2}$ follow the order

$C l_{2} > I_{2} > B r_{2}$

$I_{2} > B r_{2} > C l_{2}$

$I_{2} = C l_{2} = B r_{2}$

$C l_{2} > B r_{2} > I_{2}$

As we move from top to bottom in halogen family the bond energy of the molecules decreases as the bond distance increases. As the bond distance increases it requires less energy to break the bond i.e. less bond energy.
So, the order of bond energy of the molecules is $C l_{2} > B r_{2} > I_{2}$ .

Q. The bond dissociation energy of Cl2​,Br2​ and I2​ follow the order

Cl2​>I2​>Br2​

I2​>Br2​>Cl2​

I2​=Cl2​=Br2​

Cl2​>Br2​>I2​