The bond angle in water molecule is less than in ammonia molecule, due to the

Question

The bond angle in water molecule is less than in ammonia molecule, due to the (A) presence of two lone pairs in H2O molecule (B) presence of three lone pairs in H2O molecule (C) presence of two lone pairs in NH3 molecule (D) high electronegativity of oxygen atom

Tardigrade Admin · Accepted Answer

The shape of ammonia molecule is trigonal pyramidal due to repulsion between lp-bp (which is more than bp-bp repulsion). Thus, the and between the bond pairs in ammonia is reduced to 107o from 109.5o .

Q. The bond angle in water molecule is less than in ammonia molecule, due to the

presence of two lone pairs in $H_{2} O$ molecule

presence of three lone pairs in $H_{2} O$ molecule

presence of two lone pairs in $N H_{3}$ molecule

high electronegativity of oxygen atom

The shape of ammonia molecule is trigonal pyramidal due to repulsion between $lp - b p$ (which is more than $b p - b p$ repulsion). Thus, the and between the bond pairs in ammonia is reduced to $107^{o}$ from $109.5^{o}$ .

Q. The bond angle in water molecule is less than in ammonia molecule, due to the

presence of two lone pairs in H2​O molecule

presence of three lone pairs in H2​O molecule

presence of two lone pairs in NH3​ molecule

high electronegativity of oxygen atom

The shape of ammonia molecule is trigonal pyramidal due to repulsion between lp−bp (which is more than bp−bp repulsion). Thus, the and between the bond pairs in ammonia is reduced to 107o from 109.5o .

presence of two lone pairs in $H_{2} O$ molecule

presence of three lone pairs in $H_{2} O$ molecule

presence of two lone pairs in $N H_{3}$ molecule

The shape of ammonia molecule is trigonal pyramidal due to repulsion between $lp - b p$ (which is more than $b p - b p$ repulsion). Thus, the and between the bond pairs in ammonia is reduced to $107^{o}$ from $109.5^{o}$ .