The binding energy per nucleon of deuteron ( 12 H ) and helium nucleus . 24 He ) is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

Question

The binding energy per nucleon of deuteron ( 12 H ) and helium nucleus . 24 He ) is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is (A) 13.9 MeV (B) 26.9 MeV (C) 23.6 MeV (D) 19.2 MeV

Tardigrade Admin · Accepted Answer

Total binding energy for (each deuteron) =2 × 1.1=2.2 MeV Total binding energy for helium =4 × 7=28 MeV ∴ Energy released =28-(2 × 2.2) =28-4.4=23.6 MeV

Q. The binding energy per nucleon of deuteron $(_{1}^{2} H)$ and helium nucleus $_{2}^{4} He)$ is $1.1 M e V$ and $7 M e V$ respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

$13.9 M e V$

$26.9 M e V$

$23.6 M e V$

$19.2 M e V$

Total binding energy for (each deuteron)
$= 2 \times 1.1 = 2.2 M e V$
Total binding energy for helium $= 4 \times 7 = 28 M e V$
$∴$ Energy released $= 28 - (2 \times 2.2)$
$= 28 - 4.4 = 23.6 M e V$

Q. The binding energy per nucleon of deuteron (12​H) and helium nucleus 24​He) is 1.1MeV and 7MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

13.9MeV

26.9MeV

23.6MeV

19.2MeV