1. Tardigrade
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  4. The binding energy per nucleon of deuteron ( 12 H ) and helium nucleus . 24 He ) is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

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Q. The binding energy per nucleon of deuteron $\left({ }_{1}^{2} H \right)$ and helium nucleus $\left.{ }_{2}^{4} He \right)$ is $1.1\, MeV$ and $7 \,MeV$ respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

NTA AbhyasNTA Abhyas 2020Atoms

Solution:

Total binding energy for (each deuteron)
$=2 \times 1.1=2.2\, MeV$
Total binding energy for helium $=4 \times 7=28\, MeV$
$\therefore $ Energy released $=28-(2 \times 2.2)$
$=28-4.4=23.6\, MeV$