The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV , respectively. When two deuterium nuclei fuse to form a helium nucleus, the energy released in the fusion is

Question

The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV , respectively. When two deuterium nuclei fuse to form a helium nucleus, the energy released in the fusion is (A) 23.6MeV (B) 2.2MeV (C) 28.0MeV (D) 30.2MeV

Tardigrade Admin · Accepted Answer

1H2+ 1H2 arrow 2He4+ΔE The binding energy per nucleon of a deuteron =1.1MeV &there4; Total binding energy =2× 1.1=2.2MeV The binding energy per nucleon of a helium nuclei =7MeV &there4; Total binding energy =4× 7=28MeV Hence, the energy released ΔE=(.28-2× 2.2.)=23.6MeV

Q. The binding energy per nucleon in deuterium and helium nuclei are $1.1 M e V$ and $7.0 M e V$ , respectively. When two deuterium nuclei fuse to form a helium nucleus, the energy released in the fusion is

$23.6 M e V$

$2.2 M e V$

$28.0 M e V$

$30.2 M e V$

Q. The binding energy per nucleon in deuterium and helium nuclei are 1.1MeV and 7.0MeV , respectively. When two deuterium nuclei fuse to form a helium nucleus, the energy released in the fusion is

23.6MeV

2.2MeV

28.0MeV

30.2MeV

_1H2​+_1H2​→_2He4​+ΔE The binding energy per nucleon of a deuteron =1.1MeV ∴ Total binding energy =2×1.1=2.2MeV The binding energy per nucleon of a helium nuclei =7MeV ∴ Total binding energy =4×7=28MeV Hence, the energy released ΔE=(28−2×2.2)=23.6MeV

Q. The binding energy per nucleon in deuterium and helium nuclei are $1.1 M e V$ and $7.0 M e V$ , respectively. When two deuterium nuclei fuse to form a helium nucleus, the energy released in the fusion is

$23.6 M e V$

$2.2 M e V$

$28.0 M e V$

$30.2 M e V$