The binding energy per nucleon for a deuteron and an α -particle are x1 and x2 respectively. The energy (Q) released in the reaction 12 H + 12 H arrow 24 He + Q is :

Question

The binding energy per nucleon for a deuteron and an α -particle are x1 and x2 respectively. The energy (Q) released in the reaction 12 H + 12 H arrow 24 He + Q is : (A) 2(.x2-x1.) (B) 2(.x1+x2.) (C) 4(.x1+x2.) (D) 4(.x2-x1.)

Tardigrade Admin · Accepted Answer

H12+ 12H arrow 2He4+Q (B ⋅ E/A) text is 1H2 arrow x1 text and 2He4 arrow x2 Q=4x2-4x1=4(x2 - x1)

Q. The binding energy per nucleon for a deuteron and an $α$ -particle are x₁ and x₂respectively. The energy (Q) released in the reaction
$_{1}^{2} H +_{1}^{2} H \to_{2}^{4} He + Q$ is :

$2 (x 2 - x 1)$

$2 (x_{1} + x_{2})$

$4 (x_{1} + x_{2})$

$4 (x_{2} - x_{1})$

$H_{1}^{2} +_1^{2} H \to_2 H e_{4} + Q$
$\frac{B \cdot E}{A} is_1 H_{2} \to x_{1} and_2 H e_{4} \to x_{2}$
$Q = 4 x_{2} - 4 x_{1} = 4 (x_{2} - x_{1})$

Q. The binding energy per nucleon for a deuteron and an α -particle are x1 and x2 respectively. The energy (Q) released in the reaction 12​H+12​H→24​He+Q is :

2(x2−x1)

2(x1​+x2​)

4(x1​+x2​)

4(x2​−x1​)