The binding energy per nucleon for a 6 C 12 nucleus is (Nuclear mass of 6 C 12=12.00000 a.m.u. Mass of hydrogen nucleus =1.007825 a.m.u Mass of neutron =1.008665 a.m.u)

Question

The binding energy per nucleon for a 6 C 12 nucleus is (Nuclear mass of 6 C 12=12.00000 a.m.u. Mass of hydrogen nucleus =1.007825 a.m.u Mass of neutron =1.008665 a.m.u) (A) 2.675 MeV (B) 7.675 MeV (C) 0 MeV (D) 3.675 MeV

Tardigrade Admin · Accepted Answer

Δ m=6 mp+(12-6) mn-mN mp= mass of proton, mn= mass of neutron, mN= mass of nucleus. or Δ m=6 × 1.007825+6(1.008665)-12

Q. The binding energy per nucleon for a $_{6} C^{12}$ nucleus is
(Nuclear mass of $_{6} C^{12} = 12.00000$ a.m.u.
Mass of hydrogen nucleus $= 1.007825$ a.m.u
Mass of neutron $= 1.008665$ a.m.u)

2.675 MeV

7.675 MeV

0 MeV

3.675 MeV

$Δ m = 6 m_{p} + (12 - 6) m_{n} - m_{N}$
$m_{p} =$ mass of proton,
$m_{n} =$ mass of neutron,
$m_{N} =$ mass of nucleus.
or $Δ m = 6 \times 1.007825 + 6 (1.008665) - 12$

Q. The binding energy per nucleon for a 6​C12 nucleus is (Nuclear mass of 6​C12=12.00000 a.m.u. Mass of hydrogen nucleus =1.007825 a.m.u Mass of neutron =1.008665 a.m.u)