Question

The binding energy per nucleon for a $ _{6} C ^{12}$ nucleus is
(Nuclear mass of ${ }_{6} C ^{12}=12.00000$ a.m.u.
Mass of hydrogen nucleus $=1.007825$ a.m.u
Mass of neutron $=1.008665$ a.m.u)

• A. 2.675 MeV
• B. 7.675 MeV
• C. 0 MeV
• D. 3.675 MeV

Answer 1

Answer: (B)

$\Delta m=6 m_{p}+(12-6) m_{n}-m_{N}$
$m_{p}=$ mass of proton,
$m_{n}=$ mass of neutron,
$m_{N}=$ mass of nucleus.
or $\Delta m=6 \times 1.007825+6(1.008665)-12$