The binding energies of nuclei X and Y are E1 and E2, respectively. Two atoms of X fuse to give one atom of Y and an energy Q is released. Then,

Question

The binding energies of nuclei X and Y are E1 and E2, respectively. Two atoms of X fuse to give one atom of Y and an energy Q is released. Then, (A) Q=2 E1-E2 (B) Q=E2-2 E1 (C) Q < 2 E1-E2 (D) Q > E2-2 E1

Tardigrade Admin · Accepted Answer

During fusion, binding energy of daughter nucleus is always greater than the total binding energy of the parent nuclei. The difference of binding energies is released. Hence, Q=E2-2 E1

Q. The binding energies of nuclei $X$ and $Y$ are $E_{1}$ and $E_{2}$ , respectively. Two atoms of $X$ fuse to give one atom of $Y$ and an energy $Q$ is released. Then,

$Q = 2 E_{1} - E_{2}$

$Q = E_{2} - 2 E_{1}$

$Q < 2 E_{1} - E_{2}$

$Q > E_{2} - 2 E_{1}$

During fusion, binding energy of daughter nucleus is always greater than the total binding energy of the parent nuclei. The difference of binding energies is released. Hence,
$Q = E_{2} - 2 E_{1}$

Q. The binding energies of nuclei X and Y are E1​ and E2​, respectively. Two atoms of X fuse to give one atom of Y and an energy Q is released. Then,

Q=2E1​−E2​

Q=E2​−2E1​

Q<2E1​−E2​

Q>E2​−2E1​