Question

The best reagent for converting $2$ -phenylpropanamide into $2$ -phenylpropanamine is

• A. $B{r}_2$ in aqueous $NaOH$
• B. excess of $H_2$
• C. iodine in the presence of red phosphorus
• D. $LiAl{H}_4$

Answer 1

Answer: (D)

Correct answer is (d) $LiAl{H}_4$