Question

The best explanation for the solubility of $MnS$ in dilute $HCl$ is that :

• A. Solubility product of $MnC{l}_2$ is less than that of $MnS$
• B. Concentration of $M{n}^{2+}$ is lowered by the formation of complex ions with chloride ions
• C. Concentration of sulphide ions is lowered by oxidation to free sulphur
• D. Concentration of sulphide ions is lowered by formation of weak acid $H_{2}S$

Answer 1

Answer: (D)

$MnS(s)\rightleftharpoons M{n}^{2+}(aq)+S^{2-}(aq)$
$S^{2-}(aq)+2H^{+}(aq)\rightleftharpoons H_{2}S(aq)$