Question

The best explanation for the solubility of $MnS$ in dilute $HCl$ is that :

• A. Solubility product of $MnCl_2$ is less than that of $MnS$
• B. Concentration of $Mn^{2+}$ is lowered by the formation of complex ions with chloride ions
• C. Concentration of sulphide ions is lowered by oxidation to free sulphur
• D. Concentration of sulphide ions is lowered by formation of weak acid $H_2S$

Answer 1

Answer: (D)

$MnS ( s ) \rightleftharpoons Mn ^{2+}( aq )+ S ^{2-}( aq )$
$S ^{2-}( aq )+2 H ^{+}( aq ) \rightleftharpoons H _{2} S ( aq )$