The BCl3 is a planar molecule whereas NCl3 is pyramidal, because:

Question

The BCl3 is a planar molecule whereas NCl3 is pyramidal, because: (A) nitrogen atom is smaller than boron atoms (B)  B-Cl bond is more polar than N-Cl bond. (C)  N-Cl bond is more covalent than B-Cl bond (D)  BCl3 has no lone pair but NCl3 has a lone pair of electrons

Tardigrade Admin · Accepted Answer

In boron trichloride, boron is sp2 hybridised and there is no lone pair on boron while in nitrogen. It is sp3 hybridised and there is a lone pair of electron in nitrogen. Hence, due to this reson BCl3 is a planer molecule and NCl3 is a pyramidal molecule.

Q. The $BC l_{3}$ is a planar molecule whereas $NC l_{3}$ is pyramidal, because:

nitrogen atom is smaller than boron atoms

$B - Cl$ bond is more polar than $N - Cl$ bond.

$N - Cl$ bond is more covalent than $B - Cl$ bond

$BC l_{3}$ has no lone pair but $NC l_{3}$ has a lone pair of electrons

In boron trichloride, boron is $s p^{2}$ hybridised and there is no lone pair on boron while in nitrogen. It is $s p^{3}$ hybridised and there is a lone pair of electron in nitrogen. Hence, due to this reson $BC l_{3}$ is a planer molecule and $NC l_{3}$ is a pyramidal molecule.

Q. The BCl3​ is a planar molecule whereas NCl3​ is pyramidal, because:

nitrogen atom is smaller than boron atoms

B−Cl bond is more polar than N−Cl bond.

N−Cl bond is more covalent than B−Cl bond

BCl3​ has no lone pair but NCl3​ has a lone pair of electrons

In boron trichloride, boron is sp2 hybridised and there is no lone pair on boron while in nitrogen. It is sp3 hybridised and there is a lone pair of electron in nitrogen. Hence, due to this reson BCl3​ is a planer molecule and NCl3​ is a pyramidal molecule.

Q. The $BC l_{3}$ is a planar molecule whereas $NC l_{3}$ is pyramidal, because:

$B - Cl$ bond is more polar than $N - Cl$ bond.

$N - Cl$ bond is more covalent than $B - Cl$ bond

$BC l_{3}$ has no lone pair but $NC l_{3}$ has a lone pair of electrons

In boron trichloride, boron is $s p^{2}$ hybridised and there is no lone pair on boron while in nitrogen. It is $s p^{3}$ hybridised and there is a lone pair of electron in nitrogen. Hence, due to this reson $BC l_{3}$ is a planer molecule and $NC l_{3}$ is a pyramidal molecule.