The back-side attack on 2-bromobutane by methoxide (.CH3O-.) gives the product shown below. Which Fischer projection represents 2-bromobutane used as the reactant in this reaction?

Question

The back-side attack on 2-bromobutane by methoxide (.CH3O-.) gives the product shown below. Which Fischer projection represents 2-bromobutane used as the reactant in this reaction? Question

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(C)

(D)

Tardigrade Admin · Accepted Answer

In SN2 reaction, inversion takes place, so configuration get reversed. Solution

Q. The back-side attack on 2-bromobutane by methoxide $(C H_{3} O^{-})$ gives the product shown below. Which Fischer projection represents 2-bromobutane used as the reactant in this reaction?

In $S_{N} 2$ reaction, inversion takes place, so configuration get reversed.

Q. The back-side attack on 2-bromobutane by methoxide (CH3​O−) gives the product shown below. Which Fischer projection represents 2-bromobutane used as the reactant in this reaction?

In SN​2 reaction, inversion takes place, so configuration get reversed.

Q. The back-side attack on 2-bromobutane by methoxide $(C H_{3} O^{-})$ gives the product shown below. Which Fischer projection represents 2-bromobutane used as the reactant in this reaction?

In $S_{N} 2$ reaction, inversion takes place, so configuration get reversed.