Question

The axis of the parabola $x^2+2xy+y^2-5x+5y-5=0$ is

• A. $x+y=0$
• B. $x+y-1=0$
• C. $x-y+1=0$
• D. $x-y=\frac{1}{\sqrt{2}}$

Answer 1

Answer: (A)

Given, equation
$x^2+2xy+y^2-5x+5y-5=0$
$\Rightarrow (x+y{)}^2=5x-5y+5$
$\Rightarrow (x+y{)}^2=5(x-y+1)$
$\therefore$ Axis of the parabola is $x+y=0$