The average value of rotational kinetic energy of one mole of oxygen gas at temperature T will be

Question

The average value of rotational kinetic energy of one mole of oxygen gas at temperature T will be (A) RT (B) (3/2)RT (C) (5/2)RT (D) (1/2)RT

Tardigrade Admin · Accepted Answer

The average K.E for each degree of freedom and for each mole is (1/2) R T . Since, there are two rotational degree of freedom, average rotational K . E = 2. (1/2) R T = R T

Q. The average value of rotational kinetic energy of one mole of oxygen gas at temperature $T$ will be

$RT$

$\frac{3}{2} RT$

$\frac{5}{2} RT$

$\frac{1}{2} RT$

The average K.E for each degree of freedom and for each mole is $\frac{1}{2} RT .$ Since, there are two rotational degree of freedom, average rotational $K . E = 2. \frac{1}{2} RT = RT$

Q. The average value of rotational kinetic energy of one mole of oxygen gas at temperature T will be

RT

23​RT

25​RT

21​RT