Question

The average value of rotational kinetic energy of one mole of oxygen gas at temperature $T$ will be

• A. $RT$
• B. $\frac{3}{2}RT$
• C. $\frac{5}{2}RT$
• D. $\frac{1}{2}RT$

Answer 1

Answer: (A)

The average K.E for each degree of freedom and for each mole is $\frac{1}{2} R T .$ Since, there are two rotational degree of freedom, average rotational $K . E = 2. \frac{1}{2} R T = R T$