Question

The average power dissipated in a pure capacitance $AC$ circuit is

• A. $CV$
• B. zero
• C. $\frac{1}{C{V}^2}$
• D. $\frac{1}{4}C{V}^2$

Answer 1

Answer: (B)

Average power in AC circuit is given by
$P=V_{rms}{I}_{rms}\cos \varphi$
For pure capacitive circuit $\varphi =90^{\circ }$
so $P=0.$