The average kinetic energy of a hydrogen gas molecule at NTP will be (Boltzmann's constant k=1.38× 10-23J/K

Question

The average kinetic energy of a hydrogen gas molecule at NTP will be (Boltzmann's constant k=1.38× 10-23J/K  (A)  0.186× 10-20J  (B)  0.372× 10-20J  (C)  0.56× 10-20J  (D)  5.6× 10-20J

Tardigrade Admin · Accepted Answer

Average kinetic energy =(3/2)kT T is absolute temperature =273 text K KE=(3/2)× 1.38× 10-23× 273 KE=0.56× 10-20J

Q. The average kinetic energy of a hydrogen gas molecule at NTP will be (Boltzmann's constant $k = 1.38 \times 10^{- 23} J / K$

$0.186 \times 10^{- 20} J$

$0.372 \times 10^{- 20} J$

$0.56 \times 10^{- 20} J$

$5.6 \times 10^{- 20} J$

Average kinetic energy $= \frac{3}{2} k T$ T is absolute temperature $= 273 K$ $K E = \frac{3}{2} \times 1.38 \times 10^{- 23} \times 273$ $K E = 0.56 \times 10^{- 20} J$

Q. The average kinetic energy of a hydrogen gas molecule at NTP will be (Boltzmann's constant k=1.38×10−23J/K

0.186×10−20J

0.372×10−20J

0.56×10−20J

5.6×10−20J