Question

The average kinetic energy of a hydrogen gas molecule at NTP will be (Boltzmann's constant $ k=1.38\times {{10}^{-23}}J/K $

• A. $ 0.186\times {{10}^{-20}}J $
• B. $ 0.372\times {{10}^{-20}}J $
• C. $ 0.56\times {{10}^{-20}}J $
• D. $ 5.6\times {{10}^{-20}}J $

Answer 1

Answer: (C)

Average kinetic energy $ =\frac{3}{2}kT $ T is absolute temperature $ =273\text{ }K $ $ KE=\frac{3}{2}\times 1.38\times {{10}^{-23}}\times 273 $ $ KE=0.56\times {{10}^{-20}}J $