The average e.m.f. induced in a coil in which current changes from 0.2 ampere to 0.4 ampere in 0.1s is 1 volt, the self inductance of the coil is

Question

The average e.m.f. induced in a coil in which current changes from 0.2 ampere to 0.4 ampere in 0.1s is 1 volt, the self inductance of the coil is (A) 0.2 H (B) 0.4 H (C) 0.5 H (D) 1H

Tardigrade Admin · Accepted Answer

E.m.f. induced in a coil is given by, ε = L (dI/dt) i.e. L = (E/dl/dt) Here ε = IV , dI = (0.4 - 0.2) = 0.2A and dt = 0.1s ∴ L = l/(0.2/0.1) = 1/2 = 0.5 H

Q. The average e.m.f. induced in a coil in which current changes from 0.2 ampere to 0.4 ampere in 0.1s is 1 volt, the self inductance of the coil is

0.2 H

0.4 H

0.5 H

1H

E.m.f. induced in a coil is given by, $ε = L \frac{d I}{d t} i . e . L = \frac{E}{d l / d t}$
Here $ε$ = IV , dI = (0.4 - 0.2) = 0.2A and dt = 0.1s $∴$ L = l/(0.2/0.1) = 1/2 = 0.5 H

Q. The average e.m.f. induced in a coil in which current changes from 0.2 ampere to 0.4 ampere in 0.1s is 1 volt, the self inductance of the coil is

0.2 H

0.4 H

0.5 H

1H

E.m.f. induced in a coil is given by, ε=LdtdI​i.e.L=dl/dtE​ Here ε = IV , dI = (0.4 - 0.2) = 0.2A and dt = 0.1s ∴ L = l/(0.2/0.1) = 1/2 = 0.5 H

E.m.f. induced in a coil is given by, $ε = L \frac{d I}{d t} i . e . L = \frac{E}{d l / d t}$
Here $ε$ = IV , dI = (0.4 - 0.2) = 0.2A and dt = 0.1s $∴$ L = l/(0.2/0.1) = 1/2 = 0.5 H