The average distance traversed by a molecule of gas at temperature T between two successive collisions is called its mean free path which can be expressed by (P is pressure of gas, K is boltzmann constant, d diameter of molecule)

Question

The average distance traversed by a molecule of gas at temperature T between two successive collisions is called its mean free path which can be expressed by (P is pressure of gas, K is boltzmann constant, d diameter of molecule) (A) (1/√2 π d2P) (B) (P/√2 π d2T) (C) (KT/√2 π d2P) (D) (KP/√2 π d2T)

Tardigrade Admin · Accepted Answer

Correct answer is (c) (KT/√2 π d2P)

Q. The average distance traversed by a molecule of gas at temperature T between two successive collisions is called its mean free path which can be expressed by (P is pressure of gas, K is boltzmann constant, d diameter of molecule)

$\frac{1}{2 π d ^{2} P}$

$\frac{P}{2 π d ^{2} T}$

$\frac{K T}{2 π d ^{2} P}$

$\frac{K P}{2 π d ^{2} T}$

Correct answer is (c) $\frac{K T}{2 π d ^{2} P}$

Q. The average distance traversed by a molecule of gas at temperature T between two successive collisions is called its mean free path which can be expressed by (P is pressure of gas, K is boltzmann constant, d diameter of molecule)

2​πd2P1​

2​πd2TP​

2​πd2PKT​

2​πd2TKP​

Correct answer is (c) 2​πd2PKT​

$\frac{1}{2 π d ^{2} P}$

$\frac{P}{2 π d ^{2} T}$

$\frac{K T}{2 π d ^{2} P}$

$\frac{K P}{2 π d ^{2} T}$

Correct answer is (c) $\frac{K T}{2 π d ^{2} P}$