The atomic weights of two elements A and B are 40 u and 80 u respectively. If x g of A contains y atoms, how many atoms are present in 2 x g of B :

Question

The atomic weights of two elements A and B are 40 u and 80 u respectively. If x g of A contains y atoms, how many atoms are present in 2 x g of B : (A) (y/2) (B) (y/4) (C) y (D) 2 y

Tardigrade Admin · Accepted Answer

Number of moles of A =( x /40) Number of atoms of A =( x /40) × Avogadro no. = y (say) Or x=(40 y/ text Avogadro no. ) Number of moles of B =(2 x /80) Number of atoms of B =(2 x/80) × Av . no =(2/80) × (40 y / Av . no .) × Av . no .= y

Q. The atomic weights of two elements $A$ and $B$ are $40 u$ and $80 u$ respectively. If $x$ g of A contains y atoms, how many atoms are present in $2 xg$ of $B$ :

$\frac{y}{2}$

$\frac{y}{4}$

$y$

$2 y$

Q. The atomic weights of two elements A and B are 40u and 80u respectively. If x g of A contains y atoms, how many atoms are present in 2xg of B :

2y​

4y​

y

2y

Number of moles of A=40x​ Number of atoms of A=40x​× Avogadro no. =y (say) Or x= Avogadro no. 40y​ Number of moles of B=802x​ Number of atoms of B =802x​×Av.no=802​×Av.no.40y​×Av.no.=y

Q. The atomic weights of two elements $A$ and $B$ are $40 u$ and $80 u$ respectively. If $x$ g of A contains y atoms, how many atoms are present in $2 xg$ of $B$ :

$\frac{y}{2}$

$\frac{y}{4}$

$y$

$2 y$