The atomic weights of two elements A and B are 40 and 80 respectively. If x g of A contains y atoms, how many atoms are present in 2x g of B?

Question

The atomic weights of two elements A and B are 40 and 80 respectively. If x g of A contains y atoms, how many atoms are present in 2x g of B? (A) (Y/2) (B) (Y/4) (C) Y (D) 2Y

Tardigrade Admin · Accepted Answer

Atomic mass 40 80 given weigh x gram 2x gram No. of mole (x/40) (2x/80) But according to question =(x/40)× NA=Y

Q. The atomic weights of two elements $A$ and $B$ are $40$ and $80$ respectively. If $xg$ of $A$ contains $y$ atoms, how many atoms are present in $2 xg$ of $B$ ?

$\frac{Y}{2}$

$\frac{Y}{4}$

$Y$

$2 Y$

Atomic mass 40 80

given weigh x gram 2x gram

No. of mole $\frac{x}{40}$ $\frac{2 x}{80}$

But according to question $= \frac{x}{40} \times N_{A} = Y$

Atomic mass	40	80
given weigh	x gram	2x gram
No. of mole	$\frac{x}{40}$	$\frac{2 x}{80}$

Q. The atomic weights of two elements A and B are 40 and 80 respectively. If xg of A contains y atoms, how many atoms are present in 2xg of B?

2Y​

4Y​

Y

2Y

Atomic mass 40 80 given weigh x gram 2x gram No. of mole 40x​ 802x​ But according to question =40x​×NA​=Y

Q. The atomic weights of two elements $A$ and $B$ are $40$ and $80$ respectively. If $xg$ of $A$ contains $y$ atoms, how many atoms are present in $2 xg$ of $B$ ?

$\frac{Y}{2}$

$\frac{Y}{4}$

$Y$

$2 Y$

Atomic mass 40 80

given weigh x gram 2x gram

No. of mole $\frac{x}{40}$ $\frac{2 x}{80}$

But according to question $= \frac{x}{40} \times N_{A} = Y$