The atomic weight of thorium is 232 and atomic no Z = 90. Disintegration of thorium finally gives Pb for which A = 208 and Z = 82. For this process the number of α and β particles respectively are

Question

The atomic weight of thorium is 232 and atomic no Z = 90. Disintegration of thorium finally gives Pb for which A = 208 and Z = 82. For this process the number of α and β particles respectively are (A) 4 and 6 (B) 6 and 4 (C) 3 and 2 (D) 2 and 3

Tardigrade Admin · Accepted Answer

90Th232 xrightarrow[]82Pb208 Number of α-particles =(232-208/4)=6 Number of P-particles =6× 2-(90-82)=4

Q. The atomic weight of thorium is 232 and atomic no Z = 90. Disintegration of thorium finally gives Pb for which A = 208 and Z = 82. For this process the number of $α$ and $β$ particles respectively are

4 and 6

6 and 4

3 and 2

2 and 3

$_{90} T h^{232}_{82} P b^{208}$
Number of $α$ -particles
$= \frac{232 - 208}{4} = 6$
Number of P-particles
$= 6 \times 2 - (90 - 82) = 4$

Q. The atomic weight of thorium is 232 and atomic no Z = 90. Disintegration of thorium finally gives Pb for which A = 208 and Z = 82. For this process the number of α and β particles respectively are