The atomic weight of Fe is 56 . The weight of Fe deposited from FeCl 3 solution by passing 0.6 F of electricity is

Question

The atomic weight of Fe is 56 . The weight of Fe deposited from FeCl 3 solution by passing 0.6 F of electricity is (A) 5.6 g (B) 11.2 ,g (C) 22.4 g (D) 33.6 g

Tardigrade Admin · Accepted Answer

Eq. weight of Fe =56 / 3 w Fe =E Fe × No. of Faradays =(56/3) × 0.6=11.2 g

Q. The atomic weight of $F e$ is $56.$ The weight of $F e$ deposited from $F e C l_{3}$ solution by passing $0.6 F$ of electricity is

$5.6 g$

$11.2, g$

$22.4 g$

$33.6 g$

Eq. weight of $F e = 56/3$

$w_{F e} = E_{F e} \times$ No. of Faradays $= \frac{56}{3} \times 0.6 = 11.2 g$

Q. The atomic weight of Fe is 56. The weight of Fe deposited from FeCl3​ solution by passing 0.6F of electricity is

5.6g

11.2,g

22.4g

33.6g