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Q. The atomic weight of $Fe$ is $56 .$ The weight of $Fe$ deposited from $FeCl _{3}$ solution by passing $0.6 F$ of electricity is

Electrochemistry

Solution:

Eq. weight of $Fe =56 / 3$

$w_{ Fe }=E_{ Fe } \times$ No. of Faradays $=\frac{56}{3} \times 0.6=11.2\, g$