The atomic weight of Al is 27. When a current of 5 F is passed through a solution of Al3+ ions, the weight of Al deposited is

Question

The atomic weight of Al is 27. When a current of 5 F is passed through a solution of Al3+ ions, the weight of Al deposited is (A) 27 g (B) 36 g (C) 45 g (D) 39 g

Tardigrade Admin · Accepted Answer

Al 3++3 e- longrightarrow Al Equivalent weight of Al =( text atomic weight of Al /3)=(27/3)=9 Weight of Al = equivalent weight of Al × number of Faradays =9 × 5=45 g

Q. The atomic weight of $A l$ is $27$ . When a current of $5 F$ is passed through a solution of $A l^{3 +}$ ions, the weight of $A l$ deposited is

27 g

36 g

45 g

39 g

$A l^{3 +} + 3 e^{-} ⟶ A l$
Equivalent weight of $A l$
$= \frac{atomic weight of A l}{3} = \frac{27}{3} = 9$
Weight of $A l =$ equivalent weight of $A l$
$\times$ number of Faradays
$= 9 \times 5 = 45 g$

Q. The atomic weight of Al is 27. When a current of 5F is passed through a solution of Al3+ ions, the weight of Al deposited is