1. Tardigrade
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  3. Chemistry
  4. The atomic weight of Al is 27. When a current of 5 F is passed through a solution of Al3+ ions, the weight of Al deposited is

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Q. The atomic weight of $Al$ is $27$. When a current of $5 F$ is passed through a solution of $ Al^{3+} $ ions, the weight of $Al$ deposited is

AMUAMU 2007

Solution:

$Al ^{3+}+3 e^{-} \longrightarrow Al$
Equivalent weight of $Al$
$ =\frac{\text { atomic weight of } Al }{3}=\frac{27}{3}=9 $
Weight of $ Al =$ equivalent weight of $ Al$
$ \times $ number of Faradays
$=9 \times 5=45\, g$