The atomic number (Z) of an element whose ka wavelength is λ is 11 . The atomic number of an element whose ka, wavelength is 4 λ is equal to

Question

The atomic number (Z) of an element whose ka wavelength is λ is 11 . The atomic number of an element whose ka, wavelength is 4 λ is equal to (A) 6 (B) 11 (C) 44 (D) 4

Tardigrade Admin · Accepted Answer

∴ (Z-1)2 λ = constant ∴ (102) λ =4 λ(Z-1)2 ⇒ Z =6

Q. The atomic number $(Z)$ of an element whose $k_{a}$ wavelength is $λ$ is $11$ . The atomic number of an element whose $k_{a}$ , wavelength is $4 λ$ is equal to

6

11

44

4

$∴ (Z - 1)^{2} λ =$ constant
$∴ (1 0^{2}) λ = 4 λ (Z - 1)^{2}$
$\Rightarrow Z = 6$

Q. The atomic number (Z) of an element whose ka​ wavelength is λ is 11 . The atomic number of an element whose ka​, wavelength is 4λ is equal to

6

11

44

4

∴(Z−1)2λ= constant ∴(102)λ=4λ(Z−1)2 ⇒Z=6

Q. The atomic number $(Z)$ of an element whose $k_{a}$ wavelength is $λ$ is $11$ . The atomic number of an element whose $k_{a}$ , wavelength is $4 λ$ is equal to

$∴ (Z - 1)^{2} λ =$ constant
$∴ (1 0^{2}) λ = 4 λ (Z - 1)^{2}$
$\Rightarrow Z = 6$