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  4. The atomic number (Z) of an element whose ka wavelength is λ is 11 . The atomic number of an element whose ka, wavelength is 4 λ is equal to

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Q. The atomic number $(Z)$ of an element whose $k_{a}$ wavelength is $\lambda$ is $11$ . The atomic number of an element whose $k_{a}$, wavelength is $4 \lambda$ is equal to

ManipalManipal 2014Atoms

Solution:

$\therefore (Z-1)^{2} \lambda =$ constant
$\therefore \left(10^{2}\right) \lambda =4 \lambda(Z-1)^{2} $
$\Rightarrow Z =6$