The Arrhenius plots of two reactions, I and II are shown graphically The graph suggests that

Question

The Arrhenius plots of two reactions, I and II are shown graphically <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/827cb0dc3b9a5a54a70731f4f2d8b9ef-.png" /> The graph suggests that (A) EI > EII and AI > AII (B) EII > EI and AII > AI (C) EII > EII and AI > AII (D) EII > EI and AI > AII

Tardigrade Admin · Accepted Answer

The temperature dependance of rate of a chemical reaction is expressed by Arrhenius equation,

k = A e^{- E_{a} / K T}

l n k = l n A - \frac{E _{a}}{RT}

If we compare the above equation with the equation of a straight line,

y = m x + c

∴

For the plot between

lo g k

versus

1/ T

.
slope

= - E_{a} / R

and intercept

= l n A

∴ E_{1} > E_{II}

and

A_{I} > A_{II}

Q. The Arrhenius plots of two reactions, I and II are shown graphically
The graph suggests that

$E_{I} > E_{II}$ and $A_{I} > A_{II}$

$E_{II} > E_{I}$ and $A_{II} > A_{I}$

$E_{II} > E_{II}$ and $A_{I} > A_{II}$

$E_{II} > E_{I}$ and $A_{I} > A_{II}$

Q. The Arrhenius plots of two reactions, I and II are shown graphically The graph suggests that

EI​>EII​ and AI​>AII​

EII​>EI​ and AII​>AI​

EII​>EII​ and AI​>AII​

EII​>EI​ and AI​>AII​

Q. The Arrhenius plots of two reactions, I and II are shown graphically
The graph suggests that

$E_{I} > E_{II}$ and $A_{I} > A_{II}$

$E_{II} > E_{I}$ and $A_{II} > A_{I}$

$E_{II} > E_{II}$ and $A_{I} > A_{II}$

$E_{II} > E_{I}$ and $A_{I} > A_{II}$