The arithmetic mean of the nine numbers in the given set 9,99,999, ldots 999999999 is a 9 digit number N, all whose digits are distinct. The number N does not contain the digit

Question

The arithmetic mean of the nine numbers in the given set 9,99,999, ldots 999999999 is a 9 digit number N, all whose digits are distinct. The number N does not contain the digit (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

[.: N=(1/9) 9+99+999+ ldots+999999999 =1+11 +111+ ldots+111111111 =1 2 3 4 5 6 7 8 9

Q. The arithmetic mean of the nine numbers in the given set ${9, 99, 999, \dots 999999999}$ is a $9$ digit number $N$ , all whose digits are distinct. The number $N$ does not contain the digit

$[: N = \frac{1}{9} {9 + 99 + 999 + \dots + 999999999} = 1 + 11$
$+ 111 + \dots + 111111111$
$= 123456789$

Q. The arithmetic mean of the nine numbers in the given set {9,99,999,…999999999} is a 9 digit number N, all whose digits are distinct. The number N does not contain the digit

[:N=91​{9+99+999+…+999999999}=1+11 +111+…+111111111 =123456789

Q. The arithmetic mean of the nine numbers in the given set ${9, 99, 999, \dots 999999999}$ is a $9$ digit number $N$ , all whose digits are distinct. The number $N$ does not contain the digit

$[: N = \frac{1}{9} {9 + 99 + 999 + \dots + 999999999} = 1 + 11$
$+ 111 + \dots + 111111111$
$= 123456789$