The area of the triangle with vertices A ( z ), B ( iz ) and C ( z + iz) is :

Question

The area of the triangle with vertices A ( z ), B ( iz ) and C ( z + iz) is : (A) 1 (B) (1/2)|z|2 (C) (1/2) (D) (1/2)|z+ iz |2

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/0b2958565bbbd70d65f04f839a8fb888-.png" /> A=(1/2)|z|| i z| =(|z|2/2)

Q. The area of the triangle with vertices $A (z), B (i z)$ and $C (z + i z)$ is :

1

$\frac{1}{2} ∣ z ∣^{2}$

$\frac{1}{2}$

$\frac{1}{2} ∣ z + i z ∣^{2}$

$A = \frac{1}{2} ∣ z ∣∣ i z ∣$
$= \frac{∣ z ∣ ^{2}}{2}$

Q. The area of the triangle with vertices A(z),B(iz) and C(z+iz) is :

1

21​∣z∣2

21​

21​∣z+iz∣2

A=21​∣z∣∣iz∣ =2∣z∣2​

Q. The area of the triangle with vertices $A (z), B (i z)$ and $C (z + i z)$ is :

$\frac{1}{2} ∣ z ∣^{2}$

$\frac{1}{2}$

$\frac{1}{2} ∣ z + i z ∣^{2}$

$A = \frac{1}{2} ∣ z ∣∣ i z ∣$
$= \frac{∣ z ∣ ^{2}}{2}$