The area (in square unit) of the circle which touches the lines 4x + 3y = 15 and 4x + 3y = 5 is

Question

The area (in square unit) of the circle which touches the lines 4x + 3y = 15 and 4x + 3y = 5 is (A)  4 π  (B)  3 π  (C)  2 π  (D) π

Tardigrade Admin · Accepted Answer

Since, given lines are parallel. ∴ d = (15 - 5 /42 + 32) = (10/5) ⇒ d = 2 = diameter of the circle ∴ Radius of circle = 1 ∴ Area of circle = π r2 = π sq unit

Q. The area (in square unit) of the circle which touches the lines $4 x + 3 y = 15$ and $4 x + 3 y = 5$ is

$4 π$

$3 π$

$2 π$

$π$

Since, given lines are parallel.
$∴ d = \frac{15 - 5}{4 ^{2} + 3 ^{2}} = \frac{10}{5}$
$\Rightarrow d = 2 =$ diameter of the circle
$∴$ Radius of circle $= 1$
$∴$ Area of circle = $π r^{2} = π$ sq unit

Q. The area (in square unit) of the circle which touches the lines 4x+3y=15 and 4x+3y=5 is

4π

3π

2π

π

Since, given lines are parallel. ∴d=42+3215−5​=510​ ⇒d=2= diameter of the circle ∴ Radius of circle =1 ∴ Area of circle = πr2=π sq unit

Q. The area (in square unit) of the circle which touches the lines $4 x + 3 y = 15$ and $4 x + 3 y = 5$ is

$4 π$

$3 π$

$2 π$

$π$

Since, given lines are parallel.
$∴ d = \frac{15 - 5}{4 ^{2} + 3 ^{2}} = \frac{10}{5}$
$\Rightarrow d = 2 =$ diameter of the circle
$∴$ Radius of circle $= 1$
$∴$ Area of circle = $π r^{2} = π$ sq unit