Question

The area (in sq. units) of the region bounded by the curve $x^2=4y$ and the straight line $x=4y-2$ :

• A. $\frac{5}{4}$
• B. $\frac{9}{8}$
• C. $\frac{3}{4}$
• D. $\frac{7}{8}$

Answer 1

Answer: (B)

$x=4y-2\&x^2=4y$
$\Rightarrow x^2=x+2\Rightarrow x^2-x-2=0$
$x=2,-1$
So, ${\int }_{-1}^2(\frac{x+2}{4}-\frac{x^2}{4})dx=\frac{9}{8}$