Question

The area (in sq. units) bounded by the curve $y=max.\left(x^3,x^4\right)$ and the $x$ -axis from $x=0$ to $x=1$ is

Answer 1

Answer: 0.25

$\max \left(x^3,x^4\right)=x^3(\forall x\in (0,1))$
$\therefore$ Required area $={\int }_0^1{x}^{3}dx={\left(\frac{x^4}{4}\right)}_0^1=\frac{1}{4}=0.25$ sq. units