The area bounded by the curve x2=y, x2=-y and y2=4 x-3 is

Question

The area bounded by the curve x2=y, x2=-y and y2=4 x-3 is (A) 2 / 3 (B) 1 / 3 (C) 4 / 3 (D) 1

Tardigrade Admin · Accepted Answer

Area A=2 ∫ limits01((y2+3/4)-√y) d y A=(1/3) sq. units <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/b77644f56e1e674cac007632975d420c-.png" />

Q. The area bounded by the curve $x^{2} = y, x^{2} = - y$ and $y^{2} = 4 x - 3$ is

$2/3$

$1/3$

$4/3$

1

Area $A = 2 0 \int 1 (\frac{y ^{2} + 3}{4} - y) d y$
$A = \frac{1}{3}$ sq. units

Q. The area bounded by the curve x2=y,x2=−y and y2=4x−3 is

2/3

1/3

4/3

1

Area A=20∫1​(4y2+3​−y​)dy A=31​ sq. units

Q. The area bounded by the curve $x^{2} = y, x^{2} = - y$ and $y^{2} = 4 x - 3$ is

$2/3$

$1/3$

$4/3$

Area $A = 2 0 \int 1 (\frac{y ^{2} + 3}{4} - y) d y$
$A = \frac{1}{3}$ sq. units