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Question
Mathematics
The area bounded by f (x) =x2, 0 le x le 1, g(x)=x+2,1 le x le2 and x- axis is
Q. The area bounded by
f
(
x
)
=
x
2
,
0
≤
x
≤
1
,
g
(
x
)
=
x
+
2
,
1
≤
x
≤
2
and
x
- axis is
1705
218
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VITEEE 2017
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A
2
3
B
3
4
C
3
8
D
None of these
Solution:
Required area
=
Area of
O
A
B
+
Area of
A
BC
Now, Area of
O
A
B
=
0
∫
1
f
(
x
)
d
x
+
1
∫
2
g
(
x
)
d
x
=
0
∫
1
x
2
d
x
+
∫
1
2
(
−
x
+
2
)
d
x
=
3
x
3
1
0
1
+
[
2
−
x
2
+
2
x
]
1
2
=
3
1
+
[
(
2
−
4
+
4
)
−
(
2
−
1
)
+
2
]
=
3
1
+
[
(
−
2
+
4
)
−
(
2
3
)
]
=
3
1
+
2
1
=
6
5
sq unit