We know that, the volume V of a cube of side x is given by V=x3 ⇒dxdV=3x2
Let Δx be change in side =3% of x=0.03x
Now, change in volume, ΔV=(dxdV)Δx =(3x2)Δx=(3x2)(0.03x) (as Δx=3% of x is 0.03x) =0.09x3m3
Hence, the approximate change in the volume of the cube is 0.09x3m3. ∴ The correct option is (c).