The angular speed of truck wheel is increased from 900 rpm to 2460 rpm in 26 seconds. The number of revolutions by the truck engine during this time is . (Assuming the acceleration to be uniform).

Question

The angular speed of truck wheel is increased from 900 rpm to 2460 rpm in 26 seconds. The number of revolutions by the truck engine during this time is . (Assuming the acceleration to be uniform). (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

We know, θ=((ω1+ω2/2)) t Let number of revolutions be N ∴ 2 π N =2 π((900+2460/60 × 2)) × 26 N =728

Q. The angular speed of truck wheel is increased from $900 r p m$ to $2460 r p m$ in $26$ seconds. The number of revolutions by the truck engine during this time is ________.
(Assuming the acceleration to be uniform).

We know, $θ = (\frac{ω _{1} + ω _{2}}{2}) t$
Let number of revolutions be $N$
$∴ 2 π N = 2 π (\frac{900 + 2460}{60 \times 2}) \times 26$
$N = 728$

Q. The angular speed of truck wheel is increased from 900rpm to 2460rpm in 26 seconds. The number of revolutions by the truck engine during this time is ________. (Assuming the acceleration to be uniform).

We know, θ=(2ω1​+ω2​​)t Let number of revolutions be N ∴2πN=2π(60×2900+2460​)×26 N=728

Q. The angular speed of truck wheel is increased from $900 r p m$ to $2460 r p m$ in $26$ seconds. The number of revolutions by the truck engine during this time is ________.
(Assuming the acceleration to be uniform).

We know, $θ = (\frac{ω _{1} + ω _{2}}{2}) t$
Let number of revolutions be $N$
$∴ 2 π N = 2 π (\frac{900 + 2460}{60 \times 2}) \times 26$
$N = 728$