Question

The angular speed of truck wheel is increased from $900\, rpm$ to $2460\, rpm$ in $26$ seconds. The number of revolutions by the truck engine during this time is ________.
(Assuming the acceleration to be uniform).

Answer 1

We know, $\theta=\left(\frac{\omega_{1}+\omega_{2}}{2}\right) t$
Let number of revolutions be $N$
$\therefore 2 \pi N =2 \pi\left(\frac{900+2460}{60 \times 2}\right) \times 26$
$N =728$